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The `((x++))` syntax is shorthand for `let x++`. According to `help let`:
If the last ARG evaluates to 0, let returns 1; 0 is returned
otherwise.
Thus the exit status of the expression `x=0; let x++` is 1, since the post-increment `++` operator evaluates to the value of the variable before incrementing.
In Bash 4, this non-zero exit status properly triggers `set -e`'s error trap, but in Bash 3 it does not. That's why the tests were passing on OS X (Bash 3) but not Linux (Bash 4).
We can work around the problem by choosing an incrementation expression that never evaluates to 0, such as `+=` or the pre-increment `++` operator. For consistency and clarity, I've changed to `x+=1` everywhere.
Ref. #25, #27
56 lines
1001 B
Bash
Executable File
56 lines
1001 B
Bash
Executable File
#!/usr/bin/env bash
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set -e
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count_only_flag=""
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if [ "$1" = "-c" ]; then
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count_only_flag=1
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shift
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fi
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extended_syntax_flag=""
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if [ "$1" = "-x" ]; then
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extended_syntax_flag="-x"
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shift
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fi
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trap "kill 0; exit 1" int
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count=0
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for filename in "$@"; do
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let count+="$(bats-exec-test -c "$filename")"
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done
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if [ -n "$count_only_flag" ]; then
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echo "$count"
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exit
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fi
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echo "1..$count"
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status=0
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offset=0
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for filename in "$@"; do
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index=0
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{
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IFS= read -r # 1..n
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while IFS= read -r line; do
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case "$line" in
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"begin "* )
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let index+=1
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echo "${line/ $index / $(($offset + $index)) }"
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;;
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"ok "* | "not ok "* )
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[ -n "$extended_syntax_flag" ] || let index+=1
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echo "${line/ $index / $(($offset + $index)) }"
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[ "${line:0:6}" != "not ok" ] || status=1
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;;
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* )
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echo "$line"
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;;
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esac
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done
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} < <( bats-exec-test $extended_syntax_flag "$filename" )
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offset=$(($offset + $index))
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done
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exit "$status"
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